抦傠偆両榓嶼偺悽奅両

嶼妟偵僠儍儗儞僕乮夝摎曇乯

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乕栤戣5乕

敿宎r偺墌偵嶰妏宍ABC偑撪愙偟偰偄傑偡丅捀揰C偐傜AB偵悅慄傪堷偒丄岎傢偭偨揰傪俫偲偟傑偡丅偦偺帪偺捈宎2r傪BC丒AC丒CH傪巊偭偰昞偟偰傒傛偆丅
摎.r=$\frac{BC亊CA}{2CH}$
夝朄

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揰C偐傜墌偺拞怱傪捠傞捈慄CE傪堷偒傑偡丅偦偆偡傞偲丄墌偺捈宎偵懳偡傞墌廃妏偼捈妏偵側傞偺偱丄嶰妏宍ACE偼捈妏嶰妏宍偲側傝傑偡丅
傑偨丄屖AC偵懳偡傞墌廃妏偺掕棟傛傝丄妏CBH偲妏CEA偼摨偠戝偒偝偵側傝傑偡丅
傛偭偰丄妏CBH偲妏CEA丒妏CHB偲妏CAE(捈妏)偺擇偮偺妏偑摨偠偱偁傞偺偱丄嶰妏宍BCH偲嶰妏宍ECA偑憡帡偵側傝傑偡丅

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傛偭偰曈偺斾傛傝丄 \begin{align} BC:CH=CE:CA\nonumber\\ BC:CH=2r:CA\nonumber\\ 2r亊CH=BC亊CA\nonumber\\ 2r=\frac{BC亊CA}{CH}\nonumber\\ r=\frac{BC亊CA}{2CH}\nonumber \end{align}
仸偙傟偼尰戙偺悢妛偺惓尫掕棟偵側偭偰偄傞両

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